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-2=-2x^2+9x+5
We move all terms to the left:
-2-(-2x^2+9x+5)=0
We get rid of parentheses
2x^2-9x-5-2=0
We add all the numbers together, and all the variables
2x^2-9x-7=0
a = 2; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·2·(-7)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{137}}{2*2}=\frac{9-\sqrt{137}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{137}}{2*2}=\frac{9+\sqrt{137}}{4} $
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